What is the equation of the plane which passes through the z-axis and is perpendicular to the line `(x-a)/(cos theta) = (y+2)/(sin theta) = (z-3)/0 ?` (A) `x+y tan theta=0` (B) `y+x tan theta=0` (C) `x cos theta-y sin theta=0` (D) `x sin theta-y cos theta=0`

Equation of the plane which passes through the Z-axis, and is perpendicular to the line (x-a)/(cos theta) = (y-b)/(sin theta) =(z-c)/(0) is

Find the equation of the straight line through (a cos theta, b sin theta) perpendicular to the line x/(a cos theta)+ y/(b sin theta) = 1 .

If tan theta = (x)/(y) , " then " (x sin theta + y cos theta)/( x sin theta - y cos theta) is equal to

if tan theta=(x)/(y) then sin2 theta+cos2 theta is

Eliminate theta from the following equation: x cos theta-y sin theta=a,x sin theta+y cos theta=b

The eliminant of theta from x cos theta - y sin theta = 2 , x sin theta + y cos theta = 4 will give

If (sin theta)/(x)=(cos theta)/(y) then sin theta-cos theta

The equation to the straight line passing through the point (a cos^(3)theta,a sin^(3)theta) and perpendicular to the line x sec theta+y csc theta=a is x cos theta-y sin theta=a cos2 thetax cos theta+y sin theta=a cos2 thetax sin theta+y cos theta=a cos2 theta none of these

Find (dy)/(dx) if x= 3 cos theta - cos 2theta and y= sin theta - sin 2theta.