Consider a car moving on a straight road with a speed of `100m//s`. The distance at which car can be stopped is `[mu_k=0.5]`

Consider, a car moving along a straight horizontal road with a speed of 72 km/h. If the coefficient of static friction between the tyre and the road is 0.5, the shortest distance in which the car can be stopped is (Take g=10 //s^(2) )

Consider a car moving along a straight horizontal road with a speed of 36 km/h. If the coefficient of static friction between road and tyers is 0.4, the shortest distance in which the car can be stopped is (Take g=10 m//s2)

Consider a car moving along a straight horizontal road with a speed of 36 km/h. If the coefficient of static friction between road and tyers is 0.4, the shortest distance in which the car can be stopped is (Take g=10 m//s2)

Consider a car moving along a straight horizontal road with a speed of 72 km/h. If the coefficient of static friction between the tyres and the road is 0.5, the shortest distance in which the car can be stopped is [g=10 ms^(-1)]

A car is moving on a straight road with a speed of 20 m//s . The drive of the car put the breaks at some instant which retards the car uniformly at a rate of 2 m//s^(2) , until the car stops completely then find the time (t_(0)) taken by the car and distance (d) travelled by car, from the instant the drive put the breaks till it stops:

A car is moving on a straight road with a speed of 20 m//s . The drive of the car put the breaks at some instant which retards the car uniformly at a rate of 2 m//s^(2) , until the car stops completely then find the time (t_(0)) taken by the car and distance (d) travelled by car, from the instant the drive put the breaks till it stops:

Consider a car moving along a straight horizontal road with a speed of 72 km / h . If the coefficient of kinetic friction between the tyres and the road is 0.5, the shortest distance in which the car can be stopped is [g=10ms^(-2)]