If `f(x)=|x-1|-[x]`, where `[x]` is the greatest integer less than or equal to x, then

If f(x)=x-[x], where [x] is the greatest integer less than or equal to x, then f(+1/2) is:

If f(x)=|x|+[x] , where [x] is the greatest integer less than or equal to x, the value of f(-2.5)+f(1.5) is

If f(x)=|x-1|-[x] (where [x] is greatest integer less than or equal to x ) then.

If the function f: R->R be such that f(x) = x-[x], where [x] denotes the greatest integer less than or equal to x, then f^-1(x) is

Let f(x) be defined by f(x)=x-[x],0!=x in R, where [x] is the greatest integer less than or equal to x then the number of solutions of f(x)+f((1)/(x))=1

If f(x)= x-[x],x(phi0)inR , where [x] is greatest integer less than or equal to x, then the number of solution of f(x)+f(1/x)=1 are

The funcction f(x)=x-[x]+cosx , where [x] is the greatest integer less than or equal to x, is a :

Let R be the set of real number and f:R to R be defined by f(x)=({x})/(1+[x]^(2)) , where [x] is the greatest integer less than or equal to x, and {x}=x-[x]. Which of the following statement are true? I. The range of f is a closed interval II. f is continuous on R. III. f is one - one on R.

Let f(x) be defined by f(x) = x- [x], 0!=x in R , where [x] is the greatest integer less than or equal to x then the number of solutions of f(x) +f(1/x) =1