The normal at point `(2, -4) `on `y^2 = 8x` will be

If y=mx+c is the normal at a point on the parabola y^(2)=8x whose focal distance is 8 units.Then |c|

If the normal at P(18, 12) to the parabola y^(2)=8x cuts it again at Q, then the equation of the normal at point Q on the parabola y^(2)=8x is

If the normal at P(18, 12) to the parabola y^(2)=8x cuts it again at Q, then the equation of the normal at point Q on the parabola y^(2)=8x is

The normal at P(2,4)to y^2=8x meets the parabola at Q. Then the radius of the circle on normal chord PQ as diameter is.

A tangent and a normal are drawn at the point P(2,-4) on the parabola y^(2)=8x , which meet the directrix of the parabola at the points A and B respectively. If Q (a,b) is a point such that AQBP is a square , then 2a+b is equal to :

Normal at point to the parabola y^(2)=8x where abscissa is equal to ordinate,will meet the parabola again at a point

Three normals are drawn from the point (7, 14) to the parabola x^2-8x-16 y=0 . Find the coordinates of the feet of the normals.

Three normals are drawn from the point (7, 14) to the parabola x^2-8x-16 y=0 . Find the coordinates of the feet of the normals.

Three normals are drawn from the point (7, 14) to the parabola x^(2)-8x-16y=0. Find the coordinates of the feet of the normals.

Three normals are drawn from the point (7, 14) to the parabola x^2-8x-16 y=0 . Find the coordinates of the feet of the normals.