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In searle's experiment, the diameter of ...

In searle's experiment, the diameter of the wire, as measured by a screw gauge of least count 0.001 cm is 0.500 cm. The length, measured by a scale of least count 0.1cm is 110.0cm. When a weight of 40N is suspended from the wire, its extension is measured to be 0.125 cm by a micrometer of least count 0.001 cm. Find the Young's modulus of the meterial of the wire from this data.

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In Searle's experiment, the diameter of the wire as measured by a screw gauge of least count 0.01cm is 0.050cm . The length, measured by a scale of least count 0.1cm , is 110.0cm . When a weight of 50N is suspended from the wire, the extension is measure to be 0.125 cm by a micrometer of least count 0.01cm . Find the maximum error in the measurement of Young's modulus of the material of the wire from these data..

The diameter of a wire is measured as 0.25 cm using a screw gauge of least count 0.005 cm. The percentage error is

In Searle's apparatus diameter of the wire was measured 0.05 cm by screw gauge of least count 0.001 cm. The length of wire was measured 110 cm by meter scale of least count 0.1 cm. An external load of 50 N was applied. The extension in length of wire was measured 0.125 cm by micrometer of least count 0.001 cm. Find the maximum possible error in measurement of Young's modulus.

In Searl's experiment, which is used to find Young's Modulus of elasticity, the diameter of experimental wire is D = 0.05cm (measured by a scale of least count 0.001cm ) and length is L = 110cm (measured by a scale of least count 0.1cm ). A weight of 50N causes an extension of X = 0.125 cm (measured by a micrometer of least count 0.001cm ). find the maximum possible error in the values of Young's modulus. Screw gauge and meter scale are free error.