If the velocity of a particle is `v = At + Bt^2`, where `A` and `B` are constant, then the distance travelled by it between `1 s` and `2 s` is :

If the velocity of a particle is v = At + Bt^2 . where A and B are constants, then the distance travelled by it between 1 s and 2 s is

If the velocity of a particle is nu=At+Bt^2 , where A and B are constants, then the distance tavelled by it between 1s and 2s is

If the velocity of a particle is v= At+Bt^2, where A and B constants, then the distance travelled by it between 1s and 2s is.

The instantaneous velocity of a particle moving in a straight line is given as v = alpha t + beta t^2 , where alpha and beta are constants. The distance travelled by the particle between 1s and 2s is :

the velocity of a particle varies with time as shown below the distance travelled by the travelled by the particle during t=2s"and" t= 6s. Is

If velocity of a particle is v=bs^(2) ,where b is constant and s is displacement. The acceleration of the particle as function of s is?

The momentum of a particle is P = A + Bt^(2) . Where , A and B are constant perpendicular vectors . The force acting on the particle when its acceleration is at 45^(@) with its velocity is