A `50 Hz AC` source of `20 V` is connected across `R ` and `C` as shown in figureure.

The voltage across `R` is `12 V`. The voltage across `C` is

A 50 Hz AC source of 20 V is connected across R and C as shown in figure. The voltage across R is 12 V . The voltage across C is

A 50 Hz a.c. source of 20 V is connected across R and C as shown in figure. The voltage across R is 12 V. The voltage across C is

An ac source of 50 V (r.m.s value) is connected across a series R - C circuit. If the r.m.s voltage across the resistor is 40 V, then the r.m.s voltage across the capacitor is

An ac source of 50 V (r.m.s value) is connected across a series R - C circuit. If the r.m.s voltage across the resistor is 40 V, then the r.m.s voltage across the capacitor is

An AC voltage source V=V_0siomegat is connected across resistance R and capacitance C as shown in figureure. It is given that R=1/omegaC . The peak current is I_0 . If the angular frequency of the voltage source is changed to omega/sqrt3, then the new peak current in the circuit is .

An AC voltage source V=V_0siomegat is connected across resistance R and capacitance C as shown in figureure. It is given that R=1/omegaC . The peak current is I_0 . If the angular frequency of the voltage source is changed to omega/sqrt3, then the new peak current in the circuit is .

A resistor R and the capacitor C are connected in series across an ac source of rms voltage 5V if the rms voltage across C is 3V then that across R is .

In an RC series circuit connected across and AC source of 150 V 70 Hz, the value of R is 820 Omega and voltage across it is 100V. Calculate the voltage drop across capacitor connected in series.

A diode is connected to 220V (r.m.s) a.c. in series with a capacitor as shown in the figure. What is the voltage V across the capacitor is

An ac source of voltage V=V_(m)sin omega t is connected across the resistance R as shown in figure. The phase relation between current and voltage for this circuit is