A parallelogram is fromed with`veca` and `vecb` as the sides let `vecd_(1)` and `vecd_(2)` be the diagonals of the parallelogram , them `a^(2) +b^(2)=`

One of the diagonals of parallelogram ABCD with veca and vecb as adjacent sides is veca+vecb . The other diagonal vec(BD) is

Statement 1 : If |veca + vecb| = |veca - vecb| , then veca and vecb are perpendicular to each other. Statement 2 : If the diagonals of a parallelogram are equal in magnitude, then the parallelogram is a rectangle.

Statement 1 : If |veca + vecb| = |veca - vecb| , then veca and vecb are perpendicular to each other. Statement 2 : If the diagonals of a parallelogram are equal in magnitude, then the parallelogram is a rectangle.

ABCD is parallelogram vecA, vecB, vecC and vecD are the position vectors of vecticles A, B, C, and D with respect to any origin, them:

Prove that the area of the parallelogram with diagonal veca and vecb is (1)/(2)|vecaxxvecb|

Prove that the area of the parallelogram with diagonal veca and vecb is (1)/(2)|vecaxxvecb|

Given vecC = vecA xx vecB and vecD = vecB xx vecA . What is the angle between vecC and vecD ?