evaluate `lim_(thetararrpi/4)(sqrt2-costheta-sintheta)/(4theta-pi)^2`

lim_(theta rarr pi)((sqrt(2)-cos theta-sin theta)/((4 theta-pi)^(2))

Putting x = theta- (pi) / (4) prove that lim_ (theta rarr (pi) / (4)) (sin theta-cos theta) / (theta- (pi) / (4)) = sqrt (2)

Putting x=theta-(pi)/(4)" prove that "underset(thetararr(pi)/(4))"lim"(sintheta-costheta)/(theta-(pi)/(4))=sqrt(2).

sqrt(3)costheta+sintheta=2 then theta =

Evaluate int((3sintheta-2)costheta)/(5-cos^2theta-4sintheta)d theta

Evaluate: int(costheta)(d theta)/((2+sintheta)(3+4sintheta)\

Evaluate: int_((pi)/(4))^((3pi)/(4))(costheta)/(1+sintheta)d theta

Evaluate int_(0)^(pi//2)(costheta)/((1+sintheta)(2+sintheta))d theta