Calculate the `pH` after `50.0mL` of this solution is treated with `25.0mL` of `0.1M HCI`
`K_(b)` for `NH_(3) = 1.77 xx 10^(-5) (pK_(b) ~~ 4.76)`.

Calculate the pH after 50.0mL of 0.1M NH_(3) this solution is treated with 25.0mL of 0.1M HCI K_(b) for NH_(3) = 1.77 xx 10^(-5) (pK_(b) ~~ 4.76) .

Calculate the pH of 0.10M ammonia solution. Calcualte the pH after 50.0mL of this solution is treated with 25.0mL of 0.10M HCl . The dissociation constant of ammonia, K_(b)=1.77xx10^(-5) .

Calculate the pH after 50.0 mL of 0.1 M ammonia solution is treated with 25.0 mL of 0.10 M HCl. The dissociation constant of ammonia , K_b=1.77xx10^(-5)

What is the pH of the solution formed by mixing 25.0 mL of a 0.15 M solution of NH_(3) with 25.0 mL of 0.12 M HCI ? (K_(b) " for " NH_(3)=1.8xx10^(-5))

pH of when 50mL of 0.10 M ammonia solution is treated with 50 mL of 0.05 M HCI solution :- (pK_(b) "of ammonia"=4.74)

pH of when 50mL of 0.10 M ammonia solution is treated with 50 mL of 0.05 M HCI solution :- (pK_(b) "of ammonia"=4.74)