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Acceleration of a particle under project...

Acceleration of a particle under projectile motion at the highest point of its trajectory is :

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Why does the direction of motion of a projectile become horizontal at the hightest point of its trajectory ?

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A particle is projected at angle theta with horizontal with velocity v_0 at t = 0 . Find (a) tangential and normal acceleration of the particle at t = 0 and at highest point of its trajectory. (b) the radius of curvature att = 0 and highest point. .

A particle is projected at angle theta with horizontal with velocity v_0 at t = 0 . Find (a) tangential and normal acceleration of the particle at t = 0 and at highest point of its trajectory. (b) the radius of curvature att = 0 and highest point. .

A projectile of mass m is launched with an initial velocity vec v_i making an angle theta with the horizontal as shown in figure. The projectile momentum of the particle about the origin when it is at the highest point of its trajectory is. .

The direction of velocity and acceleration of a projectile at the highest point on the trajectory are

Average velocity of a particle in projectile motion between its starting point and the highest point of its trajectory is (projectin speed = u, angle projection from horizontal = theta )