A particle of mass m is subjected to a force `vecF=F_(0)[cos (t)hati+sin(1)hatj]`. If initially (t=0) the particle was at rest, the kinetic energy of the particle as a function of time is given by:

A particle of mass m is acted upon by a force F= t^2-kx . Initially , the particle is at rest at the origin. Then

A particle of mass m is acted upon by a force F= t^2-kx . Initially , the particle is at rest at the origin. Then

At t = 0 aparticle of mass m start moving from rest due to a force vecF = F_(0) sin (omega t)hati :

A particle of mass m kept at the origin is subjected to a froce vecF=(pt-qx)hati where t is the time elapsed and x is the x co-ordinate of the position of the particle. Particle starts its motion at t=0 with zero initial velocity. If p and q are positive constants, then:

Acceleration of a particle at any time t is veca=(2thati+3t^(2)hatj)m//s^(2) .If initially particle is at rest, find the velocity of the particle at time t=2s