`sinx + cosx = 1/sqrt(2)`

int(2sinx)/((3+sin2x)dxi se q u a lto 1/2ln|(2+sinx-cosx)/(2-sinx+cosx)|-1/(sqrt(2))tan^(-1)((sinx+cosx)/(sqrt(2)))+c 1/2ln|(2+sinx-cosx)/(2-sinx+cosx)|-1/(2sqrt(2))tan^(-1)((sinx+c0sx)/(sqrt(2)))+c 1/4ln|(2+sinx-cosx)/(2-sinx+cosx)|-1/(sqrt(2))tan^(-1)((sinx+c0sx)/(sqrt(2)))+c non eoft h e s e

IfI=int(dx)/(secx+cos e cx),t h e nIe q u a l s 1/2(cosx+sinx-1/(sqrt(2))log(cos e cx-cosx))+C 1/2(sinx-cosx-1/(sqrt(2))log|cos e cx+cotx|)+C 1/(sqrt(2))(sinx+cosx+1/2"log"|cos e cx-cosx|) 1/2[sinx-cosx]-1/(sqrt(2))"log"|cos e c(x+pi/4)

IfI=int(dx)/(secx+cos e cx),t h e nIe q u a l s 1/2(cosx+sinx-1/(sqrt(2))log(cos e cx-cosx))+C 1/2(sinx-cosx-1/(sqrt(2))log|cos e cx+cotx|)+C 1/(sqrt(2))(sinx+cosx+1/2"log"|cos e cx-cosx|) 1/2[sinx-cosx]-1/(sqrt(2))"log"|cos e c(x+pi/4)

Simplify: cos^-1((sinx+cosx)/(sqrt(2)))

int(sinx+cosx)/(sqrt(1+sin2x))dx

Evaluate: int(sinx+cosx)/(sqrt(1+sin2x))\ dx

int(sinx+cosx)/(sqrt(1+sin2x))dx

I=int (sinx+cosx)/sqrt(1-sin2x) dx