Each atom of an iron bar `(5cmxx1cmxx1cm)` has a magnetic moment `1.8xx10^(-23) Am^(2)` Knowing that the density of iron is `7.78xx10^(3) kg^(-3)m` atomic weight is `56` and Avogadro's number is `6.02xx10^(23)` the magnetic moment of bar in the state of magnetic saturation will be

Each atom of an iron bar (5cmxx 1cm xx 1cm) has a magnetic moment 1.8xx10^(-23)Am^2. Knowing that the density of iron is 7.78×10 ^3 kgm -3 , atomic weight is 56 amu and avogadro's number is 6.02×10^ 23What will be the magnetic moment of the bar in the state of magnetic saturation.

Each atom of an iron bar ( 5cmxx 1cm xx 1cm ) has a magnetic moment 1*8xx10^(-23)Am^2 . (a) What will be the magnetic moment of the bar in the state of magnetic saturation. (b) What will be the torque required to place this magnetised bar perpendicular to magnetic field of 15000 gauss ? Density of iron =7*8xx10^3kg//m^3 , Atomic wt. of iron =56 , Avogadro's number =6*023xx10^(23)//gm mole.

Each atom of an iron bar (5cmxx 1cm xx 1cm) has a magnetic moment 1.8xx10^(-23)Am^2. What will be the torque required to place this magnetised bar perpendicular to magnetic field of 15000 gauss? Density of iron = 7.8xx10^3kg//m^3, Atomic wt. of iron =56, Avogadro's number = 6.023xx10^(23)//gm mole.

A bar magnet has geometric length 4.8 xx 10^(-2)m . The magnet moment of bar magnet, of pole strength 20A m is?

A bar magnet has geometric length 4.8 xx 10^(-2)m . The magnet moment of bar magnet, of pole strength 20A m is?

A short bar magnet has a magnetic moment of 10 Am^(2) .If its length is 10 cm,then the pole strength of the dipole is

A short bar magnet has a magnetic moment of 10 Am^(2) .If its length is 10 cm,then the pole strength of the dipole is