When Ag reacts with conc. HCl, then products will be :

Options

A. `AgCl, Cl_(2)`
B. `AgCl, H_(2)`
C. `AgCl, H_(2), Cl_(2)`
D. None of these

Answer

D

Explanation

`E^(@) "SRP of " Ag=0.80 V, E^(@) " SRP of " Cl^(-)=1.36V, E^(@) "SRP of" H^(+)=0.00 V`. So Ag can not oxidize `Cl^(-)` and can not reduce `H^(+)`.