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In the test for iodine, I(2) is treated ...

In the test for iodine, `I_(2)` is treated with sodium thiosulphate `(Na_(2)S_(2)O_(3))` :
`Na_(2)S_(2)O_(3)+I_(2) to NaI +..`

A

`Na_(2)S_(4)O_(6)`

B

`Na_(2)SO_(4)`

C

`Na_(2)S`

D

`Na_(3)ISO_(4)`

Text Solution

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The correct Answer is:
A
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