Home
Class 12
CHEMISTRY
NaX (Sodium salt of particular anion 'X'...

NaX (Sodium salt of particular anion 'X') gives brisk effervescence of Y with dilute HCl. On heating, NaX evolves gas Y which can be completely absorbed in conc. KOH solution and is colorless odourless gas. Hence X and Y respectively are :

A

`HSO_(3)^(-), SO_(2)`

B

`HS^(-) & H_(2)S`

C

`HCO_(3)^(-), CO_(2)`

D

`HC_(2)O_(4)^(-) &CO_(2)+CO`s

Text Solution

Verified by Experts

The correct Answer is:
C
`underset((NaX))(NaHCO_(3))+HCl to NaCl+H_(2)O + underset((Y))(CO_(2))uarr`
`2NaHCO_(3) overset(Delta)to Na_(2)CO_(3)+H_(2)O+CO_(2) uarr`
`CO_(2)+2KOH to K_(2)CO_(3)+H_(2)O+CO_(2) uarr`
`CO_(2)+2KOH to K_(2)CO_(3)+H_(2)O`
`CO_(2)` is colourless & odourless gas.
Promotional Banner

Topper's Solved these Questions

  • QUALITATIVE ANALYSIS (ANION)

    RESONANCE|Exercise Match The Column|1 Videos

  • QUALITATIVE ANALYSIS (ANION)

    RESONANCE|Exercise Single And Double Value Integer Type|3 Videos

  • QUALITATIVE ANALYSIS (ANION)

    RESONANCE|Exercise Part-II : National Standard Examination IN|9 Videos

  • QUALITATIVE ANALYSIS

    RESONANCE|Exercise INORGANIC CHMISTRY(Qualitative analysis)|35 Videos

  • QUALITATIVE ANALYSIS PART 1

    RESONANCE|Exercise A.L.P|39 Videos

Similar Questions

Explore conceptually related problems

Hydrolysis of BCl_3 gives X which on treatment with sodium carbonate produces Y, X and Y, respectively, are

A wire of an alkaline earth metal X, burnt in air and dipped in water, a gas 'Y' is evolved X and Y are respectively:-

Aqueous solution of a gas 'X' decolourises an acidified K_(2)Cr_(2)O_(7) solution and on passing H_(2)S in the solution gives white turbity 'Y'. Here 'X' and 'Y' respectively are:

A metal X reacts with water to produce a highly combustible gas Y, and a solution A. Another metal P reacts with Z to give the same gas Y, Z, Y, Z and P respectively are

A metal X on heating in nitrogen gas gives Y,Y on treatment with H_(2)O gives a colourless gas which when passed through CuSO_(4) solution gives a blue colour. Y is:

A crystalline solid 'X' reacts with dil. HCl to liberate a gas 'Y' . 'Y' decolourises acidified KMnO_4 . When a gas'Z' is slowly passed into an aqueous solution of 'Y' , colloidal sulphur is obtained . 'x' and 'Z' could be , respectively.

Sulphur on reaction with conc. H_2SO_4 gives X which on reaction with NaOH gives Y which on further reaction with dil H_2SO_4 give X again. Then X & Y are respectively: