The IUPAC name for `K_(2)[Cr(CN)_(2)O_(2)(O)_(2)NH_(3)]` is:

Options

A. potassium amminecyanoperoxodioxochromatic(V)
B. potassium amminedicyanoperoxodioxochromium(VI)
C. potassium amminecyanoperoxodioxochromium (VI)
D. potassium amminedicyanodioxoperoxochromate (VI

Answer

D

Explanation

`2K^(+)[Cr overset(-2)((CN)_(2))overset(-2)(O_(2)) overset(-4)((O)_(2))(overset(0)(NH_(3)))]^(2-)`
Oxidation state of chromium `=x+2(-1)+(-2)+2(-2)+(0)=-2`.
`:. X=+6`.
As per IUPAC name.
Complex is anionic, so metal ion will be named as chromate with +6 oxidation state. So, potassium amminedicyanodioxoperoxochromate(VI).