Home
Class 12
CHEMISTRY
Na(2)[Cr(NO)(NH(3))(C(2)O(4))(2)], u=sqr...

`Na_(2)[Cr(NO)(NH_(3))(C_(2)O_(4))_(2)], u=sqrt(3)BM`, Then total no. of electron in `d_(x^(2)-y^(2)) and d_(z^(2))` orbitals of metals:

Text Solution

Verified by Experts

The correct Answer is:
zero
In given complex, Cr is in +1 oxidation state.
Promotional Banner

Topper's Solved these Questions

  • COORDINATION COMPOUNDS

    RESONANCE|Exercise Additional Problem for Self Practice (APSP) Part-III One or more than one option correct type|7 Videos

  • COORDINATION COMPOUNDS

    RESONANCE|Exercise Additional Problem for Self Practice (APSP) Part-III Comprehension.|3 Videos

  • COORDINATION COMPOUNDS

    RESONANCE|Exercise Additional Problem for Self Practice (APSP) Part-III Match the column|1 Videos

  • CHEMISTRY IN EVERYDAY LIFE

    RESONANCE|Exercise ORGANIC CHEMISTRY(Chemistry in every day life)|31 Videos

  • D & F BLOCK ELEMENTS

    RESONANCE|Exercise INORGANIC CHEMISTRY(d & f- Block Elments)|40 Videos

Similar Questions

Explore conceptually related problems

In complex [Cr(NH_(3))_(6)[Co(C_(2)O_(4))_(3)] the total No. of ions formed are

Consider the following complex : [Cr(NH_(3))_(4)(NO_(2))_(2)]: inner orbital complex The oxidation number, number of d- electrons, number of unpaired d- electrons on the irreleation and number of isomers are respectively.