Explain the following with proper reason:
(i) Bleaching of flowers by chlorine is permanent while after bleaching with `SO_2`, the colour returns.
(ii) Iodine dissolves more in KI solution than in water.

Explanation

(i)Chlorine bleaching action is due to oxidation while that of sulphur dioxide is due to reduction. Hence, the substance bleached by `SO_2` is reoxidised by the oxygen of air to its original state.
`Cl_2` bleaches coloured material by oxidation and thus bleaching is permanent.
`Cl_2+ H_2O to 2HCl + [O]`
Coloured material + [O] `to` Colourless
On the other hand beaching by `SO_2` is by reduction and thus temporary because colourless articles are further oxidised by air.
`SO_2+2H_2O to 2H_2SO_4+ 2[H]`
Coloured material + [H] `to` Colourless `overset([O])to` coloured
(iii )`I_2` is a covalent molecule. Thus, its solubility is less in polar solvent, i.e., water . Potassium iodide combines with iodine and forms a polyhalide which is an ionic compound . Being ionic , `KI_3` is more soluble .
`KI+I_2 to KI_3 (K^(+) I_3^-)` brown solution.