Home
Class 12
CHEMISTRY
underset"Conc."(HCl) + underset"Conc."(H...

`underset"Conc."(HCl) + underset"Conc."(HNO_3)to`
In this reaction change in oxidation number of N Is ______

Text Solution

Verified by Experts

The correct Answer is:
2
Promotional Banner

Topper's Solved these Questions

  • P-BLOCK ELEMENTS (HALOGEN & NOBLE GASES)

    RESONANCE|Exercise EXERCISE-2 PART-3|15 Videos

  • P-BLOCK ELEMENTS (HALOGEN & NOBLE GASES)

    RESONANCE|Exercise EXERCISE-2 PART-4|16 Videos

  • P-BLOCK ELEMENTS (HALOGEN & NOBLE GASES)

    RESONANCE|Exercise EXERCISE-2 PART-1|16 Videos

  • P-BLOCK ELEMENT (BORON AND CARBON FAMILY)

    RESONANCE|Exercise PART - III : OLYMPIAD PROBLEMS (PREVIOUS YEARS) STAGE - V (INTERNATIONAL CHEMISTRY OLYMPIAD (IChO)) Problem 3|8 Videos

  • PERIODIC TABLE & PERIODICITY

    RESONANCE|Exercise Advanced Level Problems|107 Videos

Similar Questions

Explore conceptually related problems

underset(" hot, conc.")(NaOH+Cl_(2)) to

HCHO with conc. alkali forms two compounds. The change in oxidation number would be-

Cu+underset((conc.))(HNO_(3))to products the products formed in above reaction is

C_(6)H_(6)+HNO_(3) underset(355K)overset(Conc.H_(2)SO_(4))toX . In the given reaction X is

Conc. HNO_3 reacts with I_2 to form: