Home
Class 12
CHEMISTRY
The enantiomeric excess and observed rot...

The enantiomeric excess and observed rotation of a mixture containing 6 gm of (+)-2-butanol and 4 gm of (-)-2-butanol are respectively (if the specific rotation of enantiomerically pure (+)-2-butanol is +13.5 unit).

A

80%, + 2.7 unit

B

20%, -27 unit

C

20%, + 2.7 unit

D

80%, - 27 unit

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • STEREOISOMERISM

    RESONANCE|Exercise EXERCISE (PART II SECTION (H))|4 Videos

  • STEREOISOMERISM

    RESONANCE|Exercise EXERCISE (PART II SECTION (I))|8 Videos

  • STEREOISOMERISM

    RESONANCE|Exercise EXERCISE (PART II SECTION (F))|6 Videos

  • SOLUTIONS

    RESONANCE|Exercise Advabced Level Problems (PART-2)|35 Videos

  • STRUCTURAL IDENTIFICATION

    RESONANCE|Exercise Advanced level Problems (Part-III)|12 Videos

Similar Questions

Explore conceptually related problems

Calculate enantiomeric axcees of mixture containing 6g of (+) 2-butanol and 4g of (-) 2-butanol.

The observed rotation of 2.0 gm of a compound iin 10 mL solution in a 25 cm long prolarimeter tube + 13.4^(@) . The specific roration of compound is :

The observed rotation of 2 gram of a compound in 10ml of solution in polarimeter tube of 25cm long is +24.6^(@) . The specific rotation of the compound (in degree) is

If a mixture of 2-bromobutane has enantiomeric excess of 50% of (+)-bromobutane has

4-methoxy-2-methyl-2-butanol

A gas is found to contains 2.34 gm of nitrogen and 5.34 gm of oxygen simplest formula of the compound is :-

(R)-2-methyl-1-butanol has a specific rotation of +13.5^(@) . The specific rotation of 2-methyl-1-butanol containing 40% of the (S)-enantiomer is _____

4-dimethylamino-2-butanol

What is the observed rotation when 0.1 M solutions of (R )-2 butanol is mixed with an equal volume of 0.05M solution of recemic 2-butnol and the resulting solution is taken in a cell of 5cm long tube in a polarimeter? The specific rotation of (R -2) butonal is +13.9^(@)