If the horizontal range of a projectile be a and the maximum height attained by it is b, then prove that the velocity of projection is

If the horizontal range of projectile be (a) and the maximum height attained by it is (b) then prove that the velocity of projection is [ 2 g (b+ a^2 /(16 b)) ] ^(1//2) .

If the horizontal range of projectile be (a) and the maximum height attained by it is (b) then prove that the velocity of projection is [ 2 g (b+ a^2 /(16 b)) ] ^(1//2) .

The maximum horizontal range of a projectile is 400 m . The maximum value of height attained by it will be

If the horizontal range of a projectile is equal to the maximum height reached, then the corresponding angle of projection is ____ .

Show that maximum horizontal range is 4 times the maximum height attained by the projectile.

In oblique projection, maximum height attained by the projectile is

The horizontal range is four times the maximum height attained by a projectile . The angle of projection is