A particle is projected from point A on plane AB, so that `AB=(2u^2tantheta)/(gsqrt3)` in the figure as shown. If u is the velocity of projection, find angle `theta`.

A particle is projected at an angle theta with an initial speed u .

A particle is projected horizontally with a speed u from the top of plane inclined at an angle theta with the horizontal. How far from the point of projection will the particle strike the plane ?

A particle is projected horizontal with a speed u from the top of plane inclined at an angle theta with the horizontal. How far from the point of projection will the particle strike the plane?

A particle is projected horizontally with speed u from the top of a plane inclined at an angle theta with the horizontal. How far from the point of projection will the particle strike the plane?

A particle is projected horizontally with a speed u from the top of plane inclined at an angle theta with the horizontal. How far from the point of projection will the particle strike the plane ?

A particle is projected horizontally with a speed u from the top of plane inclined at an angle theta with the horizontal. How far from the point of projection will the particle strike the plane ?

Figure shows that particle A is projected from point P with velocity u along the plane and simultaneously another particle B with velocity v at an angle alpha with vertical. The particles collide at point Q on the plane. Then

Figure shows that particle A is projected from point P with velocity u along the plane and simultaneously another particle B with velocity v at an angle alpha with vertical. The particles collide at point Q on the plane. Then

A particle is projected horizontally with a speed ''u'' rom the top of plane incline at an angle theta with the horizontal. How far from the point of projection will the particle strike the plane ?