A lifts is tied with thick iron wires and its mass is 1000 kg. The minimum diameter of wire, If the maximum accelertion of lifts is `1.2 m//s^(2)` , is ( g `= 9.8 m //s^(2)`)

We have common experience that a thin thread breaks if pulled at its ends. Also a thin metalic wire, when pulled at the ends elongates and then contracts, when released. A lift is tied with thick iron wires and its mass is 1000kg . What should be the minimum diameter of the wire if the maximum acceleration of the lift is 1.2m/s^2 and maximum safe stress of the wire is 1.4xx10^8N/m^2 (g= 9.8m/s^2 )

A lift is tied with thick iron and its mass is 314 kg. What should be the minimum diameter of wire if the maximum acceleration of lift is 1.2(m)/(sec^2) and the maximum safe stress of the wire is 1xx10^7(N)/(m^2) ?

A lift is tied with thick iron wire and its mass is 1000kg . If the maximum acceleration of the lift is 1.2ms^(2) and the maximum stress of the wire is 1.4xx10^(8) Nm^(2) what should be the minimum diameter of the wire?

A lift is tied with a thick iton wires and its mass is 800 kg. if the maximum ac celeration of lift is 2.2 ms^(-2) and the maximum safe stress is 1.4 xx 10^8 Nm^(-2) find the minimum diameter of the wire take g =9.8 ms^(-2)

A lift of mass 1000 kg is suspended by steel wire of maximum safe stress 1.4 xx 10^(8) N//m^(2) . Find the minimum diameter of the wire, if the maximum acceleration of the lift is 1.2 ms^(-2)

The mass of lift is 500 kg. When it ascends with an acceleration of 2m//s^(2) ,the tension in the cable will be [g=10m//s^(2)]