The function `f(x) = (log(1+ax)-log(1-bx))/x` is not difined at x = 0. The value which should be assigned to f at x = 0, so that it is continuous at x = 0, is

The function f(x) = (log(1+ax)-log(1-bx))/(x) is not defined at x = 0. The value which should be assigned to f at x = 0 so that it is continuous at x = 0, is

The function f(x) = (log(1+ax)-log(1-bx))/(x) is not defined at x = 0. The value which should be assigned to f at x = 0 so that it is continuous at x = 0, is

The function f(x) = (log (1+ax) - log(1-bx))/(x) is not defined at x = 0. The value which should be assigned to f at x = 0 so that it is continuous at x = 0 is :

The function f(x)=(log(1+ax)-log(1-bx))/x is not defined at x=0 . The value which should be assigned to f at x=0 so that it is continuous at x=0 is

The function f(x) = ([log (1 + ax) - log (1-bx)])/(x) is not defined at x = 0. The value, which should be assrgned to f at x = 0. The value, which should be assrgned to f at x = 0 so that it is continuous at x = 0 is :

The function f(x) = (log(1+ax)-log(1-bx))/x is not defined at x = 0. Find the value of f(0) so that f is continuous at x = 0

f(x)=(1)/(x)["log"(1+bx)-"log"(1-ax)] is not defined at x=0 . What value is to be assigned to f (0) so that f (x) will be continuous at x=0?

If the function f(x)=(log(1+ax)-log(1-bx))/(x) is continuous at x=0, then f(0)=