Three conductors of conductances `G_(1), G_(2) " and " G_(3)` are connected in series. Find their equivalent conductance.

Two conductors of conductnaces G_(1) and G_(2) are connected in series. They are connected in parallel to another conductor of conductance G_(3) . Determine their equivalent conductance.

The conductance (G) is

Three resistors R_1, R_2, and R_3 , and are connected in series. Find out equivalent resistance of combination.

G_1,G_2, G_3 are the conductances of three conductors. When they are joined in series, their equivalent conductance will be :

Three metal rods of same lengths and same area of cross-section having conductivities 1, 2, 3 units are connected in series. Then their their effective conductivity will be

Statement I: Two solid cylindrical rods of identical size and different thermal conductivity K_1 and K_2 are connected in series. Then the equivalent thermal conductivity of two rods system is less than that value of thermal conductivity of either rod. Statement II: For two cylindrical rods of identical size and different thermal conductivity K_1 and K_2 connected in series, the equivalent thermal conductivity K is given by (2)/(K)=(1)/(K_1)+(1)/(K_2)

Statement I: Two solid cylindrical rods of identical size and different thermal conductivity K_1 and K_2 are connected in series. Then the equivalent thermal conductivity of two rods system is less than that value of thermal conductivity of either rod. Statement II: For two cylindrical rods of identical size and different thermal conductivity K_1 and K_2 connected in series, the equivalent thermal conductivity K is given by (2)/(K)=(1)/(K_1)+(1)/(K_2)

Statement I: Two solid cylindrical rods of identical size and different thermal conductivity K_1 and K_2 are connected in series. Then the equivalent thermal conductivity of two rods system is less than that value of thermal conductivity of either rod. Statement II: For two cylindrical rods of identical size and different thermal conductivity K_1 and K_2 connected in series, the equivalent thermal conductivity K is given by (2)/(K)=(1)/(K_1)+(1)/(K_2)