Two reacants `A` and `B` are present such that `[A_(0)] = 4[B_(0)]` and `t_(1//2)` of `A` and `B` are `5` and `15` mintute respectively. If both decay folliwing `I` order, how much time later will concentrations of both of them would be equal?

Two substances A and B are present such that [A]=： 4 [B] and half life of A is 5 minute and of B is 15 minute. If they start decaying at the same time following first order, how much time later will the concentration of both of them would be same

Two substance A and B are present such that [A]=4[B} and half life of A is 5 minutes and of B is 15 minutes. If they start decaying at the same time following first order, how much time later will the concentration of both of them would be the same?

Two substances A and B are present such that [A_(0)]=4[B_(0] and half-life of A is 5 minutes and that of B is 15 minutes. If they start decaying at the same time following first order kinetics after how much time the concentration of both of them would be same ?

Two substances A and B are present such that [A_(0)]=4[B_(0] and half-life of A is 5 minutes and that of B is 15 minutes. If they start decaying at the same time following first order kinetics after how much time the concentration of both of them would be same ?

The substances A(t_((1)/(2))=5" min") and B(t_((1)/(2))="15 min") follow first order kinetics, are taken is such a way that initially [A]=4[B] . The time after which the concentration of both substances will be equal is :