If n is a whole number greater than 1, then `n^2(n^2-1)` is always divisible by 8 (b) 10 (c) 12 (d) 16

If n is an odd number greater than 1, then n(n^(2)-1) is

If p is a prime number greater than 3, then (p^(2)-1) is always divisible by (a) 6 but not 12 (b) 12 but not 24(c)24 (d) None of these

n ( n+1) ( n+2) is always divisible by ?

5^(n)-1 is always divisible by (n in N)

5^(n)-1 is always divisible by (n in N)

If n is natural number & n ge 1, then (3^(2n) - 1) is always divisible by

For ninN 2^(3n)-7n-1 is always divisible by