`cos6 6^(@)+sin8 4^(@)=`

Find the value of [(sin^2 2 2^(@)+sin^2 6 8^(@))/(cos^2 2 2^(@)+cos^2 6 8^(@))+sin^2 6 3^(@)+cos6 3^(@)sin2 7^(@)]

cos ^ (6) A + sin ^ (6) A = (1) / (4) (1 + 3cos ^ (2) 2A) cos6A + sin A = (1 + 3cos22A)

[Prove the following 8cos^(3)10^(@)-8sin^(3)20^(@)-6cos10^(@)+6sin20^(@)=2sqrt(3)

(sin2^(@)+sin4^(@)+sin6^(@)+sin8^(@))/(cos1^(@)*cos2^(@)*cos5^(@))=

3(sin x + cos x )^(4) + 6(sin x - cos x )^(2) + 4(sin^(6) x + cos^(6) x )=

3(sin x- cos x )^(4) + 6(sin x+ cos x )^(2) +4 (sin ^(6) x+ cos ^(6) x)=

3(sin x- cos x )^(4) + 6(sin x+ cos x )^(2) +4 (sin ^(6) x+ cos ^(6) x)=

cos ^(2) 2x -cos ^(2) 6x = sin 4x sin 8x

cos ^(2) 2x -cos ^(2) 6x = sin 4x sin 8x

cos ^(2) 2x -cos ^(2) 6x = sin 4x sin 8x