In case of a projectile fired at an angle equally inclined to the horizontal and vertical with velocity (u). The horizontal range is:-

For a projectile first with velocity u at an angle theta with the horizontal.

From the ground, a projectile is fired at an angle of 60 degree to the horizontal with a speed of 20" m s"^(-1) The horizontal range of the projectile is

From the ground, a projectile is fired at an angle of 60 degree to the horizontal with a speed of 20" m s"^(-1) The horizontal range of the projectile is

When a projectile is fired at an angle theta w.r.t horizontal with velocity u, then its vertical component:

Vertical ranges of two projectiles fired with same speed with complementary angles with horizontal are 40m and 90m. Their horizontal range is?

A projectile is fired at an angle theta with the horizontal with velocity u. Deduce the expression for the maximum height reached by it.

A projectile is fired from horizontal at an angle theta . What are the horizontal and vertical acceleration at the highest point ?