Enthalpy of neutralization of `CH_(3)COOH` by NaOH is less than that of HCl by NaOH.
Enthalpy of neutralization of `CH_(3)COOH` is less because of the absorption of heat in the ionization process.

This question has Statement I and Statement II. Of the four choices given after the Statements, choose the one that best describes the two Statements. Statement-I : Enthalpy of neutralization of CH_3COOH by NaOH is less than that of HCl by NaOH. Statement-II : Enthalpy of neutralization of CH_3COOH is less because of the absorption of heat in the ionization process.

Enthalpy of neutralization of HCl by NaOH is -55.84 kJ/mol and by NH_(4)OH is 51.34 kJ/mol. The enthalpy of ionization of NH_(4)OH is :

Enthalpy of neutralization of HCl by NaOH is -55.84 kJ/mol and by NH_(4)OH is 51.34 kJ/mol. The enthalpy of ionization of NH_(4)OH is :

Enthalpy of neutralization of HCl by NaOH is -55.84 kJ/mol and by NH_(4)OH is -51.34 kJ/mol. The enthalpy of ionization of NH_(4)OH is :

Will the pH of CH_3COOH be more or less than 7?

The enthalpy of neutralization of NH_(4)OH and CH_(3)COOH is – 10.5 kcal/mole and enthalpy of neutralization of strong base and CH_(3)COOH is – 12.5 kcal/mole. Calculate the enthalpy of dissociation of NH_(4) OH -

Assertion :- In general, heat of neutralization of CH_(3)COOH by NaOH is less than heat of neutralization of H_(2)SO_(4) by NaOH . Reason :- H_(2)SO_(4) is a di basic acid while CH_(3)COOH is monobasic acid.

Assertion :- In general, heat of neutralization of CH_(3)COOH by NaOH is less than heat of neutralization of H_(2)SO_(4) by NaOH . Reason :- H_(2)SO_(4) is a di basic acid while CH_(3)COOH is monobasic acid.