A `1 cm xx 1 cm` square paper coated with a suitable adsorbent on both sides. The paper is dipped in a aqueous solution of glucose of volume 20 mL and concentration 20 ppm. Final concentration glucose was dropped to 19 ppm due to adsorption. Find the number of glucose particles per unit area of the paper.
A `1 cm xx 1 cm` square paper coated with a suitable adsorbent on both sides. The paper is dipped in a aqueous solution of glucose of volume 20 mL and concentration 20 ppm. Final concentration glucose was dropped to 19 ppm due to adsorption. Find the number of glucose particles per unit area of the paper.
Text Solution
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The correct Answer is:
`3.33 xx 10^(16) cm^(-2)`
Mass of glucose adsorbed `= (20 - 19) xx (20)/(10^(6)) = 2 xx 10^(-5) g.`
Moles of glucose adsorbed `= (2 xx 10^(-5))/(180) = (10^(-6))/(9).`
Number of glucose molecules `= (10^(-6))/(9) xx 6 xx 10^(23) = (20)/(3) xx 10^(16)`
Number of glucose molecules per unit area `= (1)/(2) xx (20)/(3) xx 10^(16) = 3.33 xx 10^(16) cm^(-2).`
Moles of glucose adsorbed `= (2 xx 10^(-5))/(180) = (10^(-6))/(9).`
Number of glucose molecules `= (10^(-6))/(9) xx 6 xx 10^(23) = (20)/(3) xx 10^(16)`
Number of glucose molecules per unit area `= (1)/(2) xx (20)/(3) xx 10^(16) = 3.33 xx 10^(16) cm^(-2).`
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