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For the coagulation of 200 mL of As(2)S(...

For the coagulation of 200 mL of `As_(2)S_(3)` solution, 10 mL of 1 M NaCl is required. What is the coagulating value of NaCl.

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The correct Answer is:
`50`
10 ml of 1 M Nacl contains `NaCl = 10 xx 1 = 10` milli mole
200 ml of `As_(2)S_(3)` required NaCl for the coagulation = 10 milli mole
`therefore` 1000 ml of `As_(2)S_(3)` required NaCl for the coagulation `= 10 xx 1000//200 = 50` milli mole
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