In an aqueous solutions of `D-` glucose the percentages of `alpha` and `beta` anomers at the equilibrium condition are respectively

In an aquose solution of D-Glucose the percentage of alpha and beta anomers at equilibrium condition are respectively

The percentage of alpha-D- glucose and beta-D- glucose is-

The specific rotation of alpha- glucose is +112^(@) and beta- glucose is +19^(@) and the specific rotation of the constant equilibrium mixture is +52.7^(@) . Calculate the percentage composition of anomers (alpha and beta) in the equilibrium mixture.

In an aqueous solutions of D-glucose all the following cyclic forms, besides the open-chain forms, are present in equibrium. Which of these forms is the stable and predominant at equilibrium condition?

Draw the structures of alpha -D-glucose and beta -D-glucose

The specific rotation of two glucose anomers are alpha = + 110^(@) and beta = 19^@ and for the constant equilibrium mixtures is +52.7^@ . Calculate the percentage compositions of the anomers in the equilibrium mixture.

The specific rotation of two glucose anomers are alpha = + 110^(@) and beta = 19^@ and for the constant equilibrium mixtures is +52.7^@ . Calculate the percentage compositions of the anomers in the equilibrium mixture.

Glucose shows mutarotation when it dissolves in water. The specific rotation of alpha -D glucose and beta -D- glucose is +112.2^(@) and +18.7^(@) respectively. Calculate the percentage of two anomers present at equilibrium mixture with a specific rotation of +52.6^(@) .