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0.6 moles of PCl(5), 0.3 mole of PCl(...

0.6 moles of `PCl_(5)`, 0.3 mole of `PCl_(3)` and 0.5 mole of `Cl_(2)` are taken in a 1 L flask to obtain the following equilibrium ,
`PCl_(5(g))rArrPCl_(3(g))+Cl_(2(g))` If the equilibrium constant `K_(c)` for the reaction is 0.2 Predict the direction of the reaction.

A

Forward direction

B

Backward direction

C

Direction of the reaction cannot be predicted

D

Reaction does not move in any direction

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The correct Answer is:
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For the following equilibrium PCl_(5)(g) hArr PCl_(3)(g)+Cl_(2)(g) K_(p) is formed to be equal to K_(x ) . This is attained at

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For the reaction, PCl_(5)(g)to PCl_(3)(g)+Cl_(2)(g)

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