A graph between log (x/m) and log p is straight line at an angle of `45^(@)` with intercept on y-axis equal to 0.3010. Calculate the amount of the gas adsorbed per gram of the adsobent when the pressure is 0.2 atm.

Options

A. `0.4`
B. `0.6`
C. `0.8`
D. `0.2`

Answer

A

Explanation

`"log"(x)/(m)="log K"+(1)/(n)"log p"`
`y = c + mx`
intercept `(c) = 0.30`
`log K = 0.30`
`(1)/(n)=tan 45 = 1`
`(1)/(n)=1`
`"log"(x)/(m)=0.30+1xx log 0.2`
`"log"(x)/(m) =0.30-0.70=-0.40`
`(x)/(m)=10^(-0.40)=10^(-1)xx10^(0.60)=4xx10^(-1)=0.4`