A solid compound `'X'` on heating gives `CO_(2)` gas and a residue. The residue mixed with water forms `'Y'`. On passing an excess of `CO_(2)` through `'Y'` in water , a clear solution, `'Z'` is obtained. On boiling `'Z'`, compound `'X'` is reformed. The compound `'X'` is
A
`CaCO_(3)`
B
`Na_(2)CO_(3)`
C
`K_(2)CO_(3)`
D
`Ca(HCO_(3))_(2)`
Text Solution
Verified by Experts
The correct Answer is:
A
`X overset(Delta)rarr CO_(2)+` residue Residue + water `rarr Y` (clear solution) `Y + CO_(2) Y + CO_(2) overset(H_(2)O)rarr Z` `Z overset("Boiling")rarr X` since if is producing `CO_(2)` i.e. its is carbonate salt. `CaCO_(3) overset(Delta)rarr CO_(2)+CaO` `CaC + H_(2) overset(Delta)rarr Ca(OH)_(2)` lime water `Ca(OH)_(2)+CO_(2) rarr Ca(HCO_(3))_(2)` `Ca(HCO_(3))_(2) overset(Delta)rarr CaCO_(3)+ CO_(2)+ H_(2)O` `X rarr CaCO_(3)`
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