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Oxidation number of cobalt in [Co(NH(3))...

Oxidation number of cobalt in `[Co(NH_(3))_(6)]Cl_(2)Br` is -

A

`+6`

B

Zero

C

`+3`

D

`+2`

Text Solution

Verified by Experts

The correct Answer is:
C
Let the oxidation number of Co be x
Oxidation number of `NH_(2)` is zero
Oxidation number of `Cl` is `-1`
Oxidation number of Br is `-1`
Hence, `x+6(0)-1xx2-1=0`
`therefore" "x=+3`
So, the oxidation number of corbalt in the given complex compound is `+3`.
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