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Suppose that there are three atoms A, B, C and their oxidation number are `6,-1,-2`, respectively. Then the molecular formula of compound will be.

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Since, the charge on a free compound is zero. So
`+6=(-1xx4)+(-2)`
`+6=-6`
`"or "+6=(-1xx2)+(-2xx2)`
`=-2xx(-4)=-6`
So molecular formula, `AB_(4)C` or `AB_(2)C_(2)`.
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