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Equivalent weight of H(3)PO(4) in each o...

Equivalent weight of `H_(3)PO_(4)` in each of the reaction will be respectively - `H_(3)+OH^(-)rarrH_(2)PO_(4)+H_(2)`
`H_(3)PO_(4)+2OH^(-)rarrHPO_(4)^(2-)+2H_(2)O`
`H_(3)PO_(4)+2OH^(-)rarrPO_(4)^(3-)+3H_(2)O`

A

`98,49,32.67`

B

`49,98,32.67`

C

`98,32.67,49`

D

`32.67,49,98`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the equivalent weight of \( H_3PO_4 \) in the given reactions, we will follow these steps: ### Step 1: Calculate the Molecular Weight of \( H_3PO_4 \) The molecular weight of \( H_3PO_4 \) can be calculated using the atomic weights of its constituent elements: - Hydrogen (H): 1 g/mol - Phosphorus (P): 31 g/mol - Oxygen (O): 16 g/mol The formula for \( H_3PO_4 \) is: \[ \text{Molecular weight} = (3 \times 1) + (1 \times 31) + (4 \times 16) \] Calculating this gives: \[ \text{Molecular weight} = 3 + 31 + 64 = 98 \text{ g/mol} \] ### Step 2: Determine the Number of Replaceable \( H^+ \) Ions in Each Reaction The equivalent weight of an acid is calculated using the formula: \[ \text{Equivalent weight} = \frac{\text{Molecular weight}}{\text{Number of replaceable } H^+ \text{ ions}} \] #### Reaction 1: \[ H_3PO_4 + OH^- \rightarrow H_2PO_4^- + H_2 \] In this reaction, one \( H^+ \) ion is replaced. Therefore, the number of replaceable \( H^+ \) ions = 1. \[ \text{Equivalent weight} = \frac{98}{1} = 98 \text{ g/equiv} \] #### Reaction 2: \[ H_3PO_4 + 2OH^- \rightarrow HPO_4^{2-} + 2H_2O \] In this reaction, two \( H^+ \) ions are replaced. Therefore, the number of replaceable \( H^+ \) ions = 2. \[ \text{Equivalent weight} = \frac{98}{2} = 49 \text{ g/equiv} \] #### Reaction 3: \[ H_3PO_4 + 2OH^- \rightarrow PO_4^{3-} + 3H_2O \] In this reaction, three \( H^+ \) ions are replaced. Therefore, the number of replaceable \( H^+ \) ions = 3. \[ \text{Equivalent weight} = \frac{98}{3} \approx 32.67 \text{ g/equiv} \] ### Final Results The equivalent weights of \( H_3PO_4 \) in the three reactions are: 1. For Reaction 1: 98 g/equiv 2. For Reaction 2: 49 g/equiv 3. For Reaction 3: 32.67 g/equiv ### Summary of Equivalent Weights - Reaction 1: 98 g/equiv - Reaction 2: 49 g/equiv - Reaction 3: 32.67 g/equiv
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