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The equivalent weight of FeC(2)O(4) in t...

The equivalent weight of `FeC_(2)O_(4)` in the change
`FeC_(2)O_(4)rarrFe^(3+)+CO_(2)` is

A

M/3

B

M/6

C

M/2

D

M/1

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The correct Answer is:
A
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Equivalent weight of H_(2)O_(2) is

Assertion: Equivalent weight of FeC_(2)O_(4) in the reaction, FeC_(2)O_(4)+ Oxidising agent rarr Fe^(3+)+CO_(2) is M//3 , where M is molar mass of FeC_(2)O_(4) . Reason: In theabove reaction, total two mole of electrons are given up by 1 mol e of FeC_(2)O_(4) to the oxidising agent.

Equivalent weight of (NH_(4))_(2)Cr_(2)O_(7) in the changes is: (NH)_(4)Cr_(2)O_(7)rarrN_(2)+Cr_(2)O_(3)+4H_(2)O

The equivalent weight of a species if acts as oxidant or reductant should be derived by : Eq. weight of oxidant or reductant = ("Mol. wt. of oxidant or reductant")/{("Number of electrons lost or gained by one"),("moleculae of oxidant or reductant"):} During chemical reactions, equal equivalents of one species react with same number of equivalents of other species giving same number of equivalent of products. However this is not true for reactants if they react in terms of moles. Also Molarity can be converted to normality by multiplying the molarity with valence factor or 'n' factor. Equivalent weight of Fe_(2)O_(3) in terms of its mol. weight in the change Fe_(3)O_(4)rarrFe_(2)O_(3) is

Equivalent weight of FeC_(2)O_(4) during its reaction with KMnO_(4) is:

Equivalent mass of a substance may be calculated as, Equivalent mass =("Molecular mass")/("n-factor")=("Atomic mass")/(n-factor") n-factor= Basicity of acid or acidity of base n-factor= Number of moles of electrons gainted or lost per mole of oxidising or reducing agents n-factor= Total positive or negative valency of a salt n-factor= Valency of an ion. Concept of n-factor is very important for redox as well as for non-redox reactions. Equivalent mass of ferrous oxalate FeC_(2)O_(4) in the following reaction is : FeC_(2)O_(4) to Fe^(3+) + 2CO_(2)

The no.of electrons involved in the change, Fe_(3)O_(4)rarrFe_(2)O_(3) :

The equivalent weight of oxalic acid in C_(2)H_(2)O_(4). 2H_(2)O is

Equivalent weight of KHC_(2)O_(4).3NaHC_(2)O_(4) in reaction with acidic KMnO_(4) is (M= Molar mass )

ALLEN-REDOX REACTIONS-Exercise - 1
  1. In the reaction VO+Fe(2)O(3) rarr FeO+V(2)O(5), the eq.wt. of V(2)O(5)...

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  2. In the reaction, I(2)+2S(2)O(3)^(2-) rarr 2I^(-)+S(4)O(6)^(2-). Eq...

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  3. Molecular weight of KBrO(3) is M. What is its equivalent weight, if th...

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  4. In the reaction A^(-n2)+xe^(-)rarrA^(-n1) . Here, x will be :

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  5. What would be the equivalent weight of the reductant in the reaction :...

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  6. The eq. wt. of Na(2)S(2)O(3) as reductant in the reaction, Na(2)S(2)...

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  7. The equivalent weight of FeC(2)O(4) in the change FeC(2)O(4)rarrFe^(...

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  8. What will be n-factor for Ba(MnO(4))(2) in acidic medium? (Where it be...

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  9. The number of mole of oxalate ions oxidised by one mole of MnO(4)^(-) ...

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  10. Oxidising product of substance Na(3)AsO(3) would be

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  11. In a reaction, 4 mole of electrons are transferred to 1 mole of HNO(3)...

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  12. Balance given following half reaction for the unbalanced whole reactio...

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  13. Choose the set coefficients that correctly balances the following equa...

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  14. In the reaction : MnO(4)^(-)+xH^(+)+n e^(-)rarrMn^(2+)+yH(2)O What is ...

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  15. The number of electrons required to balanced the following equation- ...

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  16. The molar mass of CuSO(4).5H(2)O is 249. Its equivalent mass in the re...

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  17. 2KMnO(4)+5H(2)S+6H^(+)rarr2Mn^(2+)+2K^(+)+5S+8H(2)O. In the above re...

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  18. The value of n in : MnO(4)^(-)+8H^(+)+n erarr Mn^(2+)+4H(2)O is

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  19. What is the value of n in the following equation : Cr(OH)(4)^(-)+OH^...

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  20. For the redox reaction Zn+NO(3)^(-)rarr Zn^(2+)+NH(4)^(-) is basic m...

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