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The enthalpy change (Delta H) for the re...

The enthalpy change `(Delta H)` for the reaction
`N_(2) (g)+3H_(2)(g) rarr 2NH_(3)(g)`
is `-92.38 kJ` at `298 K`. What is `Delta U` at `298 K`?

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Verified by Experts

`Delta U=Delta H-Delta n_(g)RT=-92.38-(-2)xx(8.314)/(1000)xx298 = -87.42 kJ`
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