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Delta H(f)^(@) for Al(2)O(3) is -1670 K...

`Delta H_(f)^(@)` for `Al_(2)O_(3)` is -1670 KJ. Calculate the enthalpy change for the reaction `4Al+3O_(2)rarr 2Al_(2)O_(3)`

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Given `2Al+(3)/(2)O_(2)rarr Al_(2)O_(3), Delta H=-1670 kJ`
Multiplying it by 2
then `4Al+3O_(2)rarr 2Al_(2)O_(3) , Delta H=2xx(-1670)=-3340 kJ`
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