The values of `Delta H` and `Delta S` for the reaction
are `170 kJ` and `170 J K^(-1)`, respectively. This reaction will be spontaneous at

Options

A. 510 K
B. 710 K
C. 910 K
D. 1110 K

Answer

D

Explanation

For spontaneous process `Delta G` must be negative so, according to Gibb's energy equation
`Delta H-T. Delta S lt 0`
`Delta H lt T Delta S`
`T gt (Delta H)/(Delta S)`
`therefore T gt (170xx1000J)/(170 JK^(-1))rArr T gt 1000 K`