Calculate the enthalpy of vaporisation per mole for ethanol. Given `DeltaS = 109.8 J K^(-1) mol^(-1)` and boiling point of ethanol is `78.5^(@)`.

Options

A. 27.35 KJ/mol
B. 32.19 KJ/mol
C. 38.70 KJ/mol
D. 42.37 KJ/mol

Answer

C

Explanation

`Delta S=(Delta H)/(T)`
`Delta H=T. Delta S=(352.5xx(109.8)/(1000))`