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For hypothetical reversible reaction 1...

For hypothetical reversible reaction
`1//2A_(2)(g) +3//2B_(2)(g) rarr AB_(3)(g), DeltaH =- 20 kJ `if standard entropies of `A_(2),B_(2)`, and `AB_(3)` are `60,40` and `50JK^(-1) mol^(-1)` respectively. The above reaction will be equilibrium at

A

400 K

B

500 K

C

250 K

D

200 K

Text Solution

Verified by Experts

The correct Answer is:
B
`(1)/(2)A_(2(g))+(3)/(2)B_(2(g))rarr AB_(3(g)) , Delta H = - 20 KJ`
`Delta S^(@)=Sigma (S^(@))_(P)-Sigma (S^(@))_(R )`
`=50-((1)/(2)xx60+(3)/(2)xx40)`
`Delta S^(@)=-40 JK^(-1)mol^(-1)`
at equilibrium `Delta G = 0`
`therefore Delta H = T. Delta S`
`T =(+20xx1000)/(-40)=500K`
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