What is the sign of `Delta G` for the process of ice melting at 283 K ?

Options

A. `Delta G gt 0`
B. `Delta G = 0`
C. `Delta G lt 0`
D. None of these

Explanation

To determine the sign of ΔG (Gibbs free energy change) for the process of ice melting at 283 K, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Process**: Ice melting is a phase transition from solid (ice) to liquid (water). This process occurs at the melting point of ice, which is 0 °C or 273 K.

2. **Identify the Temperature**: The given temperature is 283 K. To convert this to Celsius:
\[ 283 \, \text{K} - 273 = 10 \, \text{°C} \]
This means the ice is melting at a temperature above its melting point.

3. **Determine Spontaneity**: A process is spontaneous if it occurs without external intervention. The melting of ice at 10 °C is spontaneous because it is above the melting point of ice (0 °C).

4. **Relate ΔG to Spontaneity**: The sign of ΔG indicates the spontaneity of a process:
- If ΔG < 0, the process is spontaneous.
- If ΔG = 0, the system is at equilibrium.
- If ΔG > 0, the process is non-spontaneous.

5. **Conclusion**: Since the melting of ice at 283 K (10 °C) is a spontaneous process, we conclude that:
\[ \Delta G < 0 \]
Therefore, the sign of ΔG for the process of ice melting at 283 K is negative.

### Final Answer:
The sign of ΔG for the process of ice melting at 283 K is negative (ΔG < 0).