`S_(("rhombic"))+O_(2(g))rarr SO_(2(g)) , Delta H =-297.5 K J`
`S_(("monoclinic"))+O_(2(g))rarr SO_(2) , Delta H = - 300 K J`
The data can predict that -

Options

A. Rhombic sulphur is yellow in colour
B. Monoclinic sulphur has metallic lusture
C. Monoclinic sulphur is more stable
D. `Delta H` transition of `S_(R )` to `S_(M)` is endothermic

Answer

D

Explanation

`S_(R )+O_(2)rarr SO_(2) , Delta H_(1)=-297.5 kJ`
`S_(M)+O_(2)rarr SO_(2), Delta H_(2) = -300 kJ`
`S_(R )rarr S_(M) , Delta H_(3) = ?`
eq(iii) = eq(i) - eq(ii)
`Delta H_(3)=-297.5-(-300)`
`Delta H_(3)=+2.5 kJ` so, it endothermic process.