`Xg` of ethanal was subjected to combustion in a bomb calorimeter and the heat produced is `Y J`. Then

Options

A. `Delta E_(("combustion"))=-XJ`
B. `Delta E_(("combustion"))= -YJ`
C. `Delta E_(("combustion"))= -(44Y)/(X)"J mol"^(-1)`
D. `Delta H_(("combustion"))= -(44Y)/(X)"J mol"^(-1)`

Answer

C

Explanation

Heat of combustion is determined for 1 mole substane. In Bomb calorimeter heat of reaction `= Delta E`
`Xg CH_(3)CHO` produces Y Joule heat
`therefore` 1 mole `=44 g CH_(3)CHO` will produce
`(Y)/(X)xx44` Joule heat
`Delta E=(-44Y)/(X)J mol^(-1)`